(1/5)x^2+6=2x

Solution for (1/5)x^2+6=2x equation:

(1/5)x^2+6=2x

We move all terms to the left:

(1/5)x^2+6-(2x)=0


Domain of the equation: 5)x^2!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+1/5)x^2-2x+6=0

We add all the numbers together, and all the variables

-2x+(+1/5)x^2+6=0

We multiply all the terms by the denominator


-2x*5)x^2+(+6*5)x^2+1=0

We add all the numbers together, and all the variables

-2x*5)x^2+30x^2+1=0

Wy multiply elements

-10x^2=0

a = -10; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-10)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-20}=0$